-8x^2+45x-30=0

Solution for -8x^2+45x-30=0 equation:

-8x^2+45x-30=0

a = -8; b = 45; c = -30;
Δ = b2-4ac
Δ = 452-4·(-8)·(-30)
Δ = 1065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{1065}}{2*-8}=\frac{-45-\sqrt{1065}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{1065}}{2*-8}=\frac{-45+\sqrt{1065}}{-16}
$